NWUOJ
Home
ProblemSet
Source/Category
Contest
Status
Ranklist
F.A.Qs
Login
校内登录
1173: 求圆周率的值
Memory Limit:128 MB
Time Limit:1.000 S
Judge Style:Text Compare
Creator:
Submit:93
Solved:52
Submit
Submit Record
Statistics
ShowOff!
Description
求圆周率的近似值,精确\(1/n^{2}\)到\(10^{-10}\) 公式为:\(\frac{\pi^{2}}{6}=\frac{1}{1^{2}}+\frac{1}{2^{2}}+\cdots+\frac{1}{n^{2}}+\cdots\)
Input
无
Output
一行,输出圆周率,小数点后保留3位。
Source/Category
ZJOI2017
NOIP
省选
高级
洛谷
Submit
Submit Record
Statistics
ShowOff!